Heat of Combustion

Introduction:

Every chemical and physical transformation involves some change in energy. These changes may involve heat, light, electricity, or some other form of energy. The branch of chemistry, which deals with the measurement of these changes is called thermochemistry. Enthalpy is a word which means ‘heat content’. Every substance has some characteristic enthalpy because of its chemical makeup. It depends upon several factors: the total number of subatomic particles in each atom and how they are arranged; the total number of atoms in the substance and how these atoms are arranged; and the total number of molecules and how they are arranged (including any interactions between them). Because it is impossible to know all of these factors, we can not calculate the absolute value for the heat content of a substance. However, we can measure the change in heat content, which accompany chemical or physical transformations.

The energy change of a reaction that occurs at constant pressure is termed the heat of reaction or the enthalpy change. The symbol Hrxn is used to denote the enthalpy change. If heat is evolved, the reaction is exothermic (Hrxn < 0) and if heat is absorbed the reaction is endothermic (Hrxn > 0).

If the transformation only involves a change in heat energy, it is a simple matter to monitor the energy change with a thermometer. The quantity of heat either evolved or absorbed may be calculated using the equation:

q  =  m · s · T

Where q is the quantity of heat, m is the mass of the substance undergoing the change, s is the specific heat of the substance, and T is the change in temperature in °C.

The quantity of heat is measured experimentally by allowing the reaction to take place in a thermally insulated vessel called a calorimeter . Ideally, the heat liberated in the reaction would only cause an increase in the temperature of the solution. However, because no calorimeter is perfect, some of the heat "leaks" out and we must calibrate it by determining its water equivalent, WE. This can be readily determined by measuring the temperature change that occurs when a known amount of hot water is added to a known amount of cold water in the calorimeter. The heat lost by the warm water is equal to the heat gained by the cold water and the calorimeter (we will assume no heat is lost to the laboratory). For example, if:

T1 equals the temperature of 30 g of room temperature water, and
T2 equals the temperature of 50 g of warmer water just before it is added to the room temperature water, and
Tf equals the temperature after mixing,

then the heat lost by the warmer water is

qlost  =  (T2 – Tf) · 50g · 4.18 J/g°C

The specific heat of water is 4.18 J/g°C, and the density of water is assumed to be 1.00 g/mL. The heat gained by the room temperature water is

qgained  =  (Tf – T1) · 30g · 4.18 J/g°C

The heat lost to the calorimeter is the difference between the heat lost by the warmer water and that gained by the cooler water:

 qlost  –  qgained   =  (Tf –  T1) · WE

Thus, by measuring T1, T2, and Tf, the water equivalent (WE) of the calorimeter can be calculated:

Now lets look at some real numbers and see how the (WE) is determined and used. Assume that we mix 50 g of warm water with 30 g of cool water:  

Temperature of 50 g of warm water
37.9°C 
Temperature of 30 g of room temperature water
20.9°C 
Temperature after mixing
29.1°C 
qlost = 50 g · 8.8°C · 4.18 J/g°C
1841 J 
qgained = 30 g · 8.2°C · 4.18 J/g°C 
1028 J 
Heat lost to calorimeter:
813 J 

Using this data, we can calculated the WE as:

WE  =  813 J / 8.2°C  =  99 J/°C

So, now that we have the (WE), what do we do with it? Well, lets say that we want to determine the Hrxn  for the following reaction:

A  +  B     C

We first need to determine the amount of heat (qrxn) that is evolved during this reaction.  For this we will add 20.00 g of 1.00 M reactant 'A' and 15.00 g of 2.00 M reactant 'B' into the calorimeter and monitor the temperature.  During the course of the reaction, the 35.0 g of solution increases in temperature by 6.5°C.  From this increase in temperature, we can calculated the true amount of heat, qrxn , that was released:  

Heat gained by the solution = 35.00 g · 6.5°C · 4.18 J/g°C
951 J 
Heat gained by the calorimeter = 99 J/°C · 6.5°C
644 J 
True heat of the reaction, qrxn :
1595 J 

Now that we know the true amount of heat that was released, we can calculate Hrxn by simply dividing qrxn by the moles of the limiting reagent (assume that the density of this solution is 1.000 g/mL):

moles of 'A'  =  1.0 mole/liter   ·   0.020 liters  =  0.020 moles
moles of 'B'  =  2.0 moles/liter  ·  0.015 liters  =  0.030 moles

Therefore 'A' is the limiting reagent, and the Hrxn is:

-1595 J / 0.020 moles  =  -79,750 J/mol or -79.8 kJ/mol

Purpose:

In this experiment, you will determine the enthalpy of combustion, Hcomb for magnesium reacting with oxygen to form magnesium oxide:

Mg(s)  +  ½ O2(g)      MgO(s)

The most straight forward method of determining this value would be to weigh a piece of magnesium, place it in a 'bomb' calorimeter with excess oxygen and initiate the reaction with a spark.  Unfortunately, we do not have such a sophisticated piece of equipment and so must be a little bit more clever.

Method:

Since we do not possess the technology to determine this Hcomb directly, we will use Hess' law to determine it indirectly.  Basically, Hess' law states that it does not matter how many different steps a reaction goes through.  As long as the overall reactants and products are the same, then the enthalpy of reaction will be the same.  This of course is a very powerful tool since it allows us to calculate the H for reactions that would normally be difficult or impossible to measure directly.

For our study, we will need to determine the Hrxn of each of the following three reactions:  

Reaction #1:
Mg(s)
+
2 HCl(aq) 
MgCl2(aq)
+
H2(g)
Reaction #2:
MgO(s) 
+
2 HCl(aq) 
MgCl2(aq)
+
H2O(l)
Reaction #3
H2(g) 
+
½ O2(g) 
H2O(l)
   

As written, the first reaction provides one of the reactants we needed, Mg(s).  However, it requires HCl(aq) as a reactant, and generates MgCl2(aq) and H2(g) as unwanted products.  Likewise, the third reaction provides us with the other reactant we need, O2(g).  Unfortunately, it introduces H2(g) as a reactant and generates H2O(l) as an unwanted product.  Fortunately, all of these problems are solved if we consider reversing of the Reaction #2:

MgCl2(aq)  +  H2O(l)     MgO(s)  +  2 HCl(aq)

Now we can see that the MgCl2(aq) generated as a product in the first reaction is canceled by the reactant MgCl2(aq) in the second reaction.  Also, the two moles of HCl(aq) required as a reactant in the first reaction, are canceled by the two moles of HCl (aq) generated as a product in the second reaction.  Finally, the H2(g) generated as a product in the first reaction, is canceled by the H2(g) required as a reactant in the third reaction.

Therefore, the overall Hcomb for the reaction of Mg(s) with O2(g) to form MgO(s) , can be calculated as:

Hcomb  =  HReaction#1  -  HReaction#2  + HReaction#3

In this experiment you will need to determine the temperature change or T for several reactions. Throughout this discussion we have referred to T as the change in temperature. One might assume that this was simply the difference between the beginning and final temperatures as determined with a thermometer. Unfortunately, things are slightly more complicated. For a variety of reasons, including the heat capacity of the thermometer, inefficient mixing of the solution, and heat losses to the calorimeter, the temperature difference determined by the thermometer is less than the actual temperature change of the solution (see Figure below).

To correct for this we must collect a series of temperature data over the course of the reaction. The graph above is a typical plot of temperature versus time for this type of calorimeter. Notice that the initial temperature is increasing slightly over time as it warms to room temperature. At 60 seconds into the experiment, the reactants were mixed and the temperature began to rise. The maximum temperature was seen at 3 minutes and slowly began to fall. To determine the true, instantaneous temperature rise, we must extrapolate this temperature data back to the instant they were mixed, 60 seconds (dotted line). The difference between these two temperatures is the true T we need for our calculations.

Procedure:

Construction of Calorimeters

    1. Insert one Styrofoam cup into the an other to make a calorimeter.  You will need two of these calorimeters (one you will calibrate and use throughout the experiment, the other will be used to hold reagents until needed).
    2. Add a stirring bar into the calorimeter to be calibrated and place it on a magnetic stirrer.
    3. Place a block of Styrofoam on top of the calorimeter as a lid.
    4. Insert the PASCO thermocouple through the lid and clamp to a vertical upright.
    5. Adjust the height of the probe so that it does not come in contact with the stirring bar but will be totally immersed in the solution.
Determination of (WE) for Calorimeter
    1. Accurately weigh approximately 50 g of room temperature water into your second (non-calibrated) calorimeter.
    2. Start the DataStudio software monitor its temperature for several minutes.  It should not change significantly.
    3. Use a microwave oven to heat approximately 200 mL of distilled water to 50-60 °C.
    4. Accurately weigh approximately 50 g of this heated water into the calorimeter your are calibrating.
    5. Assemble your calorimeter and start acquiring data with the DataStudio Software.
    6. Adjust the rate of stirring so that good mixing is achieved but no water is splashing on the sides of the calorimeter.
    7. After 2-3 minutes of readings, add the room temperature water to your calorimeter as quickly as possible without spilling or splashing.
    8. Continue taking readings for another 5-10 minutes.  Then dump the solution, carefully rinse and dry the calorimeter.
    9. Repeat a second time.
    10. From the graphs of your time/temperature plots, determine an average T and calculate the (WE) for your calorimeter using the example above.
Determining the Enthalpy of Reaction for MgO and HCl
    1. Dispense exactly 100.0 mL of 2.00 M HCl directly into your calibrated calorimeter. Take care not to splash the acid on the sides of the calorimeter.  Use this link to determine the density of your HCl:  Density of HCl Solutions.
    2. Adjust the rate of stirring so that good mixing is achieved but no solution is splashing on the sides of the calorimeter.
    3. Start the DataStudio software and acquire temperature data for several minutes.  This will establish the baseline temperature of your HCl.
    4. After 2-3 minutes, add approximately 1.000 g of MgO to the calorimeter as quickly as possible without splashing the HCl or the powder on the sides of the calorimeter. Continue taking readings for an additional 5-10 minutes.  (Note:  MgO dust is mildly toxic by ingestion.  DO NOT INHALE the dust!)
    5. After the reaction is complete, dump the solution down the drain, carefully rinse and dry the calorimeter.
    6. Repeat a second time.
    7. From the graphs of your time/temperature plots, determine an average T.  From this you should be able to calculate the q rxn and Hrxn for this reaction.
Determining the Enthalpy of Reaction for Mg and HCl
    1. Dispense exactly 100.0 mL of 2.00 M HCl directly into your calibrated calorimeter. Take care not to splash the acid on the sides of the calorimeter.  Use this link to determine the density of your HCl:  Density of HCl Solutions.
    2. Adjust the rate of stirring so that good mixing is achieved but no solution is splashing on the sides of the calorimeter. 
    3. Cut approximately 0.400 g of Mg into 0.25 inch pieces. Be sure to remove any oxide coating with sandpaper before you weigh the Mg. (DO NOT SAND ON YOUR BENCH!).
    4. Start the DataStudio software and acquire temperature data for several minutes.  This will establish the baseline temperature of your HCl.  
    5. After 2-3 minutes, add the Mg strips to the calorimeter as quickly as possible without splashing the HCl on the sides of the calorimeter. Continue taking readings for another 5-10 minutes.
    6. After the reaction is complete, dump the solution down the drain, carefully rinse and dry the calorimeter.
    7. Repeat a second time.
    8. From the graphs of your time/temperature plots, determine an average T.  From this you should be able to calculate the q rxn and Hrxn for this reaction.
Determining the Enthalpy of Reaction for Hydrogen and Oxygen
    1. Unfortunately, this reaction is so exothermic (Explosive, ala the 'Hindenburg') that it can not be safely studied in your calorimeter.  Therefore, we will use the literature value of -285.8 kJ/mol.
Results:

Use the following table as a guide for your data collection:  


Trial 1 
Trial 2 
Initial temperature of room temperature water    
Initial temperature of warm water    
Initial temperature of 2.00 M HCl    
Weight of MgO, g    
Initial temperature of 2.00 M HCl    
Weight of Mg strip, g    

Calculations:

From your time/temperature curves, calculate:

From your T data calculate:
Conclusions:

(Updated 6/5/07 by C.R. Snelling)